In a prior post I posed a question but did not supply the answer. To refresh your memory the question is: Can a team get six hits in an inning and not score a run?
The answer is yes, and here is how it can be done.
First batter gets a single but tries to stretch it into a double, he is thrown out at second. One hit, one out and no base runner.
Second batter gets a single. While the next batter is hitting the second one tries to steal a base but is thrown out. Two hits, two outs and no one on base,
Third batter gets a single. Three hits, two outs and a man on first.
Fourth batter gets a single, the lead runner stops at second. Four hits, two outs and runners at first and second.
Fifth batter gets an infield hit, both runner advance one base and stay put. Five hits, two outs and the bases are loaded.
Sixth batter hits the ball in fair territory and before the man on third can cross home plate, the ball strikes a runner in fair territory, the runner cannot be touching a base.
Result: The runner who is struck by the batter ball is out, since the man on third did not cross home plate before the third out the run cannot count. The official scorer credits the batter with a hit. Six hits, three outs and no runs.
As an extra, if that happened they better keep the manager away from the Kool-Aid.
